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10 September, 16:31

A ball whose mass is 0.4 kg hits the floor with a speed of 4 m/s and rebounds upward with a speed of 2 m/s. If the ball was in contact with the floor for 2 ms (2multiply10-3 s), what was the average magnitude of the force exerted on the ball by the floor? Favg = N. Calculate the magnitude of the gravitational force that the Earth exerts on the ball:mg = N

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  1. 10 September, 16:53
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    We shall apply concept of impulse

    Impulse = Force x time

    = Force x 2 x 10⁻³ N. s

    impulse = change in momentum

    change in momentum

    =.4 x 4 - (-.4 x 2)

    = 2.4

    Force x 2 x 10⁻³ = 2.4

    Force = 2.4 / 2 x 10⁻³

    = 1.2 x 10³ N.

    average magnitude of the force exerted by floor = 1.2 x 10³ N

    If R be reaction force by earth

    R - mg = 1.2 x 10³

    R = 1.2 x 10³ + mg

    = 1200 +.4 x 9.8

    = 1200 + 3.92

    = 1203.92 N.
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