When cs-137 decays, it emits gamma radiation. the energy of one photon is 1.06 * 10-13 j. what is the wavelength of this radiation?

To find the solution to the problem, we would be using Planck's equation which is E = hv

Where:

E = energy

h = Planck's constant = 6.626 x 10-34 J·s

ν = frequency

Then, you’ll need a second equation which is c = λν

Where:

c = speed of light = 3 x 108 m/sec

λ = wavelength

ν = frequency

Reorder the equation to solve for frequency:ν = c/λ

Next, substitute frequency in the first equation with c/λ to get a formula you can use:

E = hν

E = hc/λ

But we are looking for the wavelength, so rearrange it more, then our final equation would be:

λ = hc / E

λ = (6.625E-34) (3.0E8 m/s) / (1.06E-13)

λ = 1.875E-12 m