Ask Question
3 July, 09:30

When cs-137 decays, it emits gamma radiation. the energy of one photon is 1.06 * 10-13 j. what is the wavelength of this radiation?

+5
Answers (1)
  1. 3 July, 09:33
    0
    To find the solution to the problem, we would be using Planck's equation which is E = hv

    Where:

    E = energy

    h = Planck's constant = 6.626 x 10-34 J·s

    ν = frequency

    Then, you’ll need a second equation which is c = λν

    Where:

    c = speed of light = 3 x 108 m/sec

    λ = wavelength

    ν = frequency

    Reorder the equation to solve for frequency:ν = c/λ

    Next, substitute frequency in the first equation with c/λ to get a formula you can use:

    E = hν

    E = hc/λ

    But we are looking for the wavelength, so rearrange it more, then our final equation would be:

    λ = hc / E

    λ = (6.625E-34) (3.0E8 m/s) / (1.06E-13)

    λ = 1.875E-12 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “When cs-137 decays, it emits gamma radiation. the energy of one photon is 1.06 * 10-13 j. what is the wavelength of this radiation? ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers