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18 May, 21:11

Charge q1 is placed a distance r0 from charge q2. What happens to the magnitude of the force on q1 due to q2 if the distance between them is reduced to r0/4?

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  1. 18 May, 21:27
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    The magnitude of the force between the two charges will be increased.

    Explanation:

    The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled
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