Ask Question
4 October, 20:44

A 0.780 m long section of cable carrying current to a car starter motor makes an angle of 60.0° with the Earth's 5.50 ✕ 10-5 T field. What is the current (in A) when the wire experiences a force of 7.00 ✕ 10-3 N?

+1
Answers (2)
  1. 4 October, 20:53
    0
    The current is 188.17Amperes

    Explanation:

    The formula for calculating the force carrying current on a conductor placed in a magnetic field is expressed as shown;

    F = BILsin (theta) where;

    F is the force on the conductor = 7.00 ✕ 10^-3 N

    B is the earth's magnetic field = 5.50 ✕ 10^-5 Tesla

    I is the current = ?

    L is the length of the conductor = 0.78m

    theta is the angle that the conductor make with the earth's magnetic field = 60.0°

    Making the current I the subject of the formula from the equation gives;

    I = F/BLsin (theta)

    Substituting the given data's in the formula to get current in the wire;

    I = 7.00 ✕ 10^-3 / (5.50 ✕ 10^-5 * 0.78 * sin60°)

    I = 7.00*10^-3/3.72*10^-5

    I = 188.17Amperes
  2. 4 October, 21:07
    0
    188 A

    Explanation:

    Parameters given:

    Length of cable, L = 0.78 m

    Angle, θ = 60º

    Magnetic field, B = 5.5 * 10^ (-5) T

    Force experienced by wire, F = 7 * 10^ (-3) N

    The force experienced by a current carrying wire of length L, due to a magnetic field B is given as:

    F = I * L * B * sinθ

    => I = F / (L * B * sinθ)

    I = (7 * 10^ (-3)) / (0.78 * 5.5 * 10^ (-5) * sin60)

    I = 188 A
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 0.780 m long section of cable carrying current to a car starter motor makes an angle of 60.0° with the Earth's 5.50 ✕ 10-5 T field. What ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers