Ask Question
11 January, 06:00

Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 170 V. An electron enters the region between them at a speed of 2.9 x 10^5 m/s by passing through a small hole in the negative plate and continues moving toward the positive plate. Assume the electric field between the plates is uniform.

(a) what is the electron's speed, in meters per second, when it is 0.1 cm from the negative plate?

+1
Answers (1)
  1. 11 January, 06:02
    0
    Electric field between plates

    V / d

    = 170 / (2 x 10⁻²)

    = 8500 N/C

    Force on electron in this field

    = 8500 x 1.6 x 10⁻¹⁹

    = 13600 x 10⁻¹⁹ N

    Acceleration

    = 13600 x 10⁻¹⁹ / 9.1 x 10⁻³¹

    a = 1494.5 x 10¹² m / s²

    s =.1 x 10⁻² m

    v² = u² + 2as

    = (2.9x 10⁵) ² + 2 x 1494.5 x 10¹² x. 1 x 10⁻²

    = 8.41 x 10¹⁰ + 299 x 10¹⁰

    = (8.41 + 299) x 10¹⁰

    v = 17.53 x 10⁵ m / s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 170 V. An electron enters the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers