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7 March, 00:26

A soccer ball is kicked horizontally off a bridge with a height of 36m. The ball travels 25m horizontally before it hits the pavement below. What was the soccer ball's speed when it was first kicked?

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  1. 7 March, 00:33
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    9.22 m/s

    Explanation:

    Vertical height, y = 36 m

    Horizontal distance, d = 25 m

    Let the initial velocity of projection is u and it is projected horizontally.

    Let t be the time taken by the ball to hit the ground.

    For horizontal motion

    horizontal distance = horizontal velocity x time

    d = u x t

    25 = u x t ... (1)

    Use second equation of motion for vertical direction

    y = 0.5 x g t², as the initial vertical velocity is zero.

    36 = 0.5 x 9.8 x t²

    t = 2.7 second

    Put in equation (1)

    25 = u x 2.7

    u = 9.22 m/s

    Thus, the initial velocity with which the ball is projected horizontally is 9.22 m/s.
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