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17 April, 22:45

a water pump pumps 3 Kg of water every second from the bottom of the well to the top of the well 50 m above if the pump uses 2000w of electrical power to accomplish the task what is the efficiency of the pump

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  1. 17 April, 22:57
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    m = mass of water pumped = 3 kg

    t = time taken to pump mass "m" of water = 1 sec

    h = depth from which the water is pumped = 50 m

    P = electrical power used by the pump = Input power = 2000 Watt

    P' = output power

    U = potential energy gained by water

    η = efficiency of the pump

    potential energy gained by water is given as

    U = mgh

    output power is given as

    Output power = Potential energy gained by water / time

    P' = mgh/t

    inserting the values

    P' = (3) (9.8) (50) / 1

    P' = 1470 Watt

    efficiency of the pump is given as

    efficiency = output power/Input power

    η = P'/P

    η = 1470/2000

    η = 0.735
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