Energy conservation

. A pool ball of mass m is shot off a 0.68 m high pool table and hits the floor with a speed

of 6.0 m/s. What was the ball's initial velocity?

7.328m/s

Explanation:

Given parameters:

height of table = 0.68m

final velocity of the ball = 6m/s

Unknown:

Initial velocity of ball = ?

Solution:

To solve this problem, we are going to employ the appropriate motion equation.

We must understand that this fall occurs in the presence of gravity;

V = U + 2gH

Where;

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height of the pool table

Since U is the unknown, let us make it the subject of the expression;

U = V - 2gH

U = 6 - (2 x 9.8 x 0.68) = 7.328m/s (deceleration)