Ask Question
9 August, 05:57

The average density of the body of a fish is 1080 kg/m3. To keep from sinking, the fish increases its volumeby inflating an internal air bladder. By what percentage must the fish increase its volume in order to beneutrally buoyant in fresh water? The density of air at room temperature is 1.2 kg/m3.

+3
Answers (1)
  1. 9 August, 06:02
    0
    f = 8 %

    Explanation:

    given,

    density of body of fish = 1080 kg/m³

    density of air = 1.2 Kg/m³

    density of water = 1000 kg/m²

    to protect the fish from sinking volume should increased by the factor f

    density of fish + density of water x increase factor = volume changes in water

    1080 + f x 1.2 = (1 + f) x 1000

    1080 + f x 1.2 = 1000 + 1000 f

    998.8 f = 80

    f = 0.0800

    f = 8 %

    the volume increase factor of fish will be equal to f = 8 %
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The average density of the body of a fish is 1080 kg/m3. To keep from sinking, the fish increases its volumeby inflating an internal air ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers