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14 September, 07:08

A spring has a spring constant of 100 N/m, and the mass hanging from is is 0.71 kg. What is the period of the spring's motion?

answers are in metres per second:

A) 1

B) 0.031

C) 0.44

D) 0.53

+2
Answers (1)
  1. 14 September, 07:20
    0
    k = spring constant of the spring = 100 N/m

    m = mass hanging from the spring = 0.71 kg

    T = Time period of the spring's motion = ?

    Time period of the oscillations of the mass hanging is given as

    T = (2π) √ (m/k)

    inserting the values in the above equation

    T = (2 x 3.14) √ (0.71 kg/100 N/m)

    T = (6.28) √ (0.0071 sec²)

    T = (6.28) (0.084) sec

    T = 0.53 sec

    hence the correct choice is D) 0.53
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