1. A baseball is thrown vertically at 16.7 m/s. What is the maimum height of the baseball?

Use energy equations first, then prove it with projectiles math.

Question

Nicky

Physics

Yesterday, 13:44

1. A baseball is thrown vertically at 16.7 m/s. What is the maimum height of the baseball?

Use energy equations first, then prove it with projectiles math.

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Answers (1)

Know the Answer?

Isaias Rowland · Answer 1

14.2 m

Explanation:

Using conservation of energy:

PE at top = KE at bottom

mgh = ½ mv²

h = v² / (2g)

h = (16.7 m/s) ² / (2 * 9.8 m/s²)

h = 14.2 m

Using kinematics:

Given:

v₀ = 16.7 m/s

v = 0 m/s

a = - 9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s) ² = (16.7 m/s) ² + 2 (-9.8 m/s²) Δy

Δy = 14.2 m

1. A baseball is thrown vertically at 16.7 m/s. What is the maimum height of the baseball?Use energy equations first, then prove it with projectiles math.

1. A baseball is thrown vertically at 16.7 m/s. What is the maimum height of the baseball?

Use energy equations first, then prove it with projectiles math.