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15 December, 05:33

When starting a foot race, a 70.0-kg sprinter exerts an average force of 650 n backward on the ground for 0.800 s. what is his final speed?

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  1. 15 December, 05:34
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    Given:

    m = 70 kg, mass

    F = 650 N, force

    t = 0.8 s, time

    Calculate the acceleration.

    a = F/m = (650 N) / (70 kg)

    = 9.2857 m/s²

    Because the initial velocity is zero, the final velocity (after time 0.8 s) is

    v = a*t = (9.2857 m/s²) * (0.8 s)

    = 7.43 m/s

    Answer: 7.43 m/s (nearest hundredth)
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