Ask Question
22 January, 21:21

At what distance from the central axis of a long straight thin wire carrying a current of 5.0 A is the magnitude of the magnetic field due to the wire equal to the strength of the Earth's magnetic field of about 5.0 * 10-5 T?

+3
Answers (1)
  1. 22 January, 21:44
    0
    The magnetic field at a given distance from a very long (essentially infinitely long) current-carrying wire is given by:

    B = μ₀I / (2πr)

    B = magnetic field strength, μ₀ = magnetic constant, I = current, r = distance from wire

    Given values:

    B = 5.0*10⁻⁵T, μ₀ = 4π*10⁻⁷H/m, I = 5.0A

    Plug in and solve for r:

    5.0*10⁻⁵ = 4π*10⁻⁷ (5.0) / (2πr)

    r = 0.02m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “At what distance from the central axis of a long straight thin wire carrying a current of 5.0 A is the magnitude of the magnetic field due ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers