A jet fighter flying at 300 m/s (just below the speed of sound) makes a turn of radius 2.25 km. (a) what is its centripetal acceleration in gs?

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Physics

10 October, 22:38

A jet fighter flying at 300 m/s (just below the speed of sound) makes a turn of radius 2.25 km. (a) what is its centripetal acceleration in gs?

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Adeline · Answer 1

The centripetal acceleration is calculated by dividing the square of the velocity by the radius of the circular path. That is,

a = v²/r

Substituting the known values with consistent units,

a = (300 m/s) ² / (2.25 x 10^3 m)

Simplifying,

a = 40 m/s²

Hence, the centripetal acceleration is equal to 40 m/s².