A force

F acts in the x - direction, its magnitude given by F = ax^2, where x is in meters and a = 5.0N/m^2

. Find the work done by this force as it acts on a particle moving from x = 0 to x = 6.0 m.

Question

30 March, 08:28

+1

Answers (1)

Know the Answer?

Joslyn Hughes · Answer 1

F = ax²

Integrating force with respect to distance yields work.

W = ax³/3

Applying limits:

W = a/3 [6³ - 0³]

W = 5/3 (216)

W = 360 Joules

A forceF acts in the x - direction, its magnitude given by F = ax^2, where x is in meters and a = 5.0N/m^2. Find the work done by this force as it acts on a particle moving from x = 0 to x = 6.0 m.