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15 December, 12:43

Kenny and Candy decided to sit on a see-saw while visiting a local play park. Candy, of mass

50 kg, sat 250 cm from the pivot of the seesaw.

(1). Where should Kenny, of 60 kg mass, sit so that a state of stable equilibrium exists?

(ii)

What should Kenny do if he wanted to elevate Candy?

(Acceleration due to gravity = 10 N kg)

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Answers (1)
  1. 15 December, 13:03
    0
    (i) 208 cm from the pivot

    (ii) Move further from the pivot

    Explanation:

    (i) Sum of the moments about the pivot of the seesaw is zero.

    ∑τ = Iα

    (50 kg) (10 N/kg) (2.5 m) + (60 kg) (10 N/kg) x = 0

    1250 Nm + 600 N x = 0

    x = - 2.08 m

    Kenny should sit 208 cm on the other side of the pivot.

    (ii) To increase the torque, Kenny should move away from the pivot.
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