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9 November, 17:36

The electric field between two parallel plates has a magnitude of 875 N/C. The positive plate is. 002 m away from the negative plate. What is the electric potential difference between the plates?

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  1. 9 November, 17:42
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    Given:

    E = 875 N/C electric field

    d = 00.002 m, distance between parallel plates

    Note that

    1 V = 1 J/C

    The electric potential difference is

    Answer: 1.8 V (nearest tenth)
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