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22 February, 17:05

a paratrooper jumps out of a plane and opens her parachute shortly afterward. 10 seconds later the upward force on the parachute is 600N. The paratrooper and parachute weigh a total of 800N. What is the acceleration at this time?

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  1. 22 February, 17:12
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    Acceleration = 2.45 m/s²

    Explanation:

    The resultant vertical force on the paratrooper = ma = upward force - total weight of both the parachute and the

    Ma = W - Fu ... Equation 1

    Where Fu = upward force on the parachute, W = combined Weight of the parachute and the paratrooper

    W = Mg ... Equation 2

    Making M the subject of formula

    M = W/g ... Equation 3

    Where M = combined mass of the parachute and the paratrooper, g = acceleration due to gravity.

    Given: W = 800 N, g = constant = 9.8 m/s²

    Substituting these values into equation 3

    W = 800/9.8

    W = 81.63 kg.

    Also Given: Fu = 600 N, W = 800 N

    Substituting these values into equation 1

    81.63a = 800 - 600

    81.63a = 200

    Dividing both side of the equation by the coefficient of a

    81.63a/81.63 = 200/81.63

    a = 2.45 m/s²

    Therefore acceleration = 2.45 m/s²
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