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26 July, 08:19

Consider a closed circuit with a 9-volt battery connected in series to a light bulb with a resistance of 3 ohms. What is the current flowing through the light bulb?

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Answers (2)
  1. 26 July, 08:22
    0
    Current flowing through the light bulb = 3 Amps

    Explanation:

    Since the light bulb is a resistive load, it can obey ohm's law

    Voltage across the battery, V = 9 volts

    Resistance of the light bulb, R = 3 ohms

    According to Ohm's law, V = IR

    I = V/R

    I = 9/3

    I = 3 Amps
  2. 26 July, 08:26
    0
    current flowing through the light bulb = 3A

    Explanation:

    current = voltage divided by Resistance

    I = V/R

    Given that,

    resistance = 3 ohms

    V = 9 volt

    current = 9 volt / 3 ohms

    = 3A

    current flowing through the light bulb = 3A
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