A spring has a spring constant of 113 N/m. How much elastic potential energy is stored in the spring when it is compressed by 0.03 m? A:0.23 j B:0.022 j C:0.051 j D: 1.70 j

= 1.7 Joules

Explanation:

The electrical potential energy is given by;

P. E = 1/2 ke²

Where, k is the spring constant, e is the extension

Therefore;

Electrical potential energy = 1/2 * 113 N/m * 0.03 m

= 1.695 Joules

= 1.7 J

0.051 J

Explanation:

K = 113 N/m

y = 0.03 m

The elastic potential energy of the system is given by

U = 1/2 K y^2 = 0.5 x 113 x 0.03 x 0.03 = 0.051 J