A kicker kicks a football toward the opponent's goal line during a game. The ball begins its flight with an initial velocity of 70 feet per second when it is kicked at a height of 2 feet by the kicker. To the nearest foot, what maximum height will the ball reach?

You may use the function:

h (t) = - 16t^2+70t+2

A. The answer cannot be determined.

B. 79 feet

C. 981 feet

D. 129 feet ... ?

Question

Kaiya Rodriguez

Physics

14 June, 16:46

A kicker kicks a football toward the opponent's goal line during a game. The ball begins its flight with an initial velocity of 70 feet per second when it is kicked at a height of 2 feet by the kicker. To the nearest foot, what maximum height will the ball reach?

You may use the function:

h (t) = - 16t^2+70t+2

A. The answer cannot be determined.

B. 79 feet

C. 981 feet

D. 129 feet ... ?

+4

Answers (2)

Know the Answer?

Katelyn Leonard · Answer 1

16t^2 + 70t + 2 - b/2a gives maximum height - 70/-32 f (70/32) = 79 B. 79 Feet

Reese Rubio · Answer 2

h (t) = - 16t^2 + 70t + 2

h' (t) = - 32t + 70

0 = - 32t + 70

32t = 70

t = 70/32

t = 35/16

Using either method, t = 35/16.

h (35/16) = - 16 (35/16) ^2 + 70 (35/16) + 2

h (35/16) = - 16 (1225/256) + 2450/16 + 2

h (35/16) = - 1225/16 + 2450/16 + 32/16

h (35/16) = 1257/16

So the maximum height is 1257/16 feet, which is 78.5625 feet.

To the nearest foot, that's 79 feet.