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22 September, 04:25

A weightlifter lifts a set of weights a vertical distance of 2 meters. If a constant net force of 350 N is exerted on the weights, what is the amount of work done on the weights?:

350N multiplied by 2m = 700

**if the weightlifter in the previous question takes a total of 2 seconds to life the weights, how much power is performed

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  1. 22 September, 04:43
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    The work done by the weightlifter, W = 700 J

    The power of the weightlifter, P = 350 watts

    Explanation:

    A weightlifter lifts a set of weights a vertical distance, s = 2 m

    The force exerted to lift the weight, F = 350 N

    The work done by the body is defined as the product of the force applied by the body to the displacement it caused.

    W = F x s

    = 350 N x 2 m

    = 700 J

    The work done by the weightlifter, W = 700 J

    The time taken by the weightlifter to lift the weight, t = 2 s

    The power is defined as the rate of body to do work. It is given by the equation,

    P = W / t

    = 700 J / 2 s

    = 350 watts

    Hence, the power of the weightlifter, P = 350 watts
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