An object starts at position - 2m with an initial velocity of - 4 m/s and a constant acceleration of + 3 m/s^2.

a. In which direction is the object traveling initially?

b. What will be the object's velocity after 1s, 2s, 3s?

c. What will the objects position be after 3s?

here is the answer

Explanation:

a) since displacement is given as a negative value, object must travelling i the negative direction (with respect to a cartesian plane).

b) after 1 second

v = u + at

v = - 4 + 3 * 1

v = - 4 + 3

v = - 1 m/s

after 2 seconds

v = - 4 + 3*2

v = - 4 + 6

v = 2 m/s

after 3 seconds

v = - 4 + 3*3

v = - 4 + 9

v = 5 m/s

c) we need to find the position after three seconds

initial velocity = u = - 4m/s

final velocity = v = 5 m/s (as previously calculated)

acceleration=3m/s²

s = ut + 1/2 * at²

s = - 4*3 + 1/2 * 3 * (3) ²

s = - 12 + 1/2 * 27

s = - 12 + 27/2

s = 1.5 meters (in the positive direction; as time has increased and acceleration in positive)

position = - 2 + 1.5 = - 0.5 meters

(s indicates distance travelled)