A transverse wave is traveling on a string stretched along the horizontal x-axis. The equation for the

vertical displacement y of the string is given by y = 0.0020 cos[? (15x - 52t) ], where all quantities are in

SI units. The maximum speed of a particle of the string is closest to

A) 0.33 m/s.

B) 0.43 m/s.

C) 0.53 m/s.

D) 0.64 m/s.

E) 0.74 m/s.

Question

Maggie

Physics

19 July, 10:27

A transverse wave is traveling on a string stretched along the horizontal x-axis. The equation for the

vertical displacement y of the string is given by y = 0.0020 cos[? (15x - 52t) ], where all quantities are in

SI units. The maximum speed of a particle of the string is closest to

A) 0.33 m/s.

B) 0.43 m/s.

C) 0.53 m/s.

D) 0.64 m/s.

E) 0.74 m/s.

+4

Answers (1)

Know the Answer?

Cayden Bauer · Answer 1

A) 0.33 m/s

Explanation:

The standard form of a transverse wave is given by

y = a cos (ω t - kx), k = 2 π / λ

Amplitude, a = 0.002 m

Wavenumber (k) = 47.12 and wavelength (λ) = 0.133 m

Time period (T) = 0.0385 s and angular frequency (ω) = 52 π rad/s

Maximum speed of the string is given by aw

Therefore; max. speed = 0.002 x 52 π = 0.327 m/s