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8 August, 17:14

How fast (in rpm) must a centrifuge rotate if a particle 7.3 cm from the axis of rotation is to experience an acceleration of 1.1*105 g's?

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  1. 8 August, 17:33
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    The formula we use here is:

    radial acceleration = ω^2 * R

    110,000 * 9.81 m/s^2 = ω^2 * 0.073 m

    ω^2 = 110,000 * 9.81 / 0.073

    ω = 3844.76 rad/s

    and since: ω = 2pi*f - - > f = ω / (2pi)

    f = 3844.76 / (2pi) = 611.91 rps = 611.91 * 60 rpm

    = 36,714.77 rpm
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