A circular wire loop of radius 15.0 cm carries a current of 2.60

a. it is placed so that thenormal to its plane makes an angle of 41.0◦with a uniform magnetic field of magnitude12.0 t. (a) calculate the magnitude of the magnetic dipole moment of the loop. (b) what is the magnitude of the torque acting on the loop?

Question

Kendra Richard

Physics

29 July, 14:08

A circular wire loop of radius 15.0 cm carries a current of 2.60

a. it is placed so that thenormal to its plane makes an angle of 41.0◦with a uniform magnetic field of magnitude12.0 t. (a) calculate the magnitude of the magnetic dipole moment of the loop. (b) what is the magnitude of the torque acting on the loop?

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Answers (1)

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Janiyah Wade · Answer 1

Part (a) : Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop

Then,

Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b) : Torque acting on the loop

T = IAB SinФ, where B = Magnetic field, Ф = Angle

Then,

T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm