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18 May, 21:01

A runner begins from rest and accelerates at a rate of 0.22 meters per second' for 15

seconds. Calculate the distance traveled by the runner while he accelerates.

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Answers (1)
  1. 18 May, 21:15
    0
    25 m

    Explanation:

    Given:

    v₀ = 0 m/s

    a = 0.22 m/s²

    t = 15 s

    Find: Δx

    Δx = v₀ t + ½ at²

    Δx = (0 m/s) (15 s) + ½ (0.22 m/s²) (15 s) ²

    Δx = 24.75 m

    Rounded to two significant figures, the runner moves a distance of 25 m.
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