A runner begins from rest and accelerates at a rate of 0.22 meters per second' for 15

seconds. Calculate the distance traveled by the runner while he accelerates.

Car

25 m

Explanation:

Given:

v₀ = 0 m/s

a = 0.22 m/s²

t = 15 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (15 s) + ½ (0.22 m/s²) (15 s) ²

Δx = 24.75 m

Rounded to two significant figures, the runner moves a distance of 25 m.