The illuminance on a surface is 3.5 lux, and the surface is 2 meters from the light source. What's the intensity of the source?

Question

Ronan Werner

Physics

19 February, 09:23

The illuminance on a surface is 3.5 lux, and the surface is 2 meters from the light source. What's the intensity of the source?

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Answers (1)

Know the Answer?

Kash Hess · Answer 1

The intensity is 49 Candelabra

Explanation:

The formula for calculation the luminous intensity is;

Luminous intensity = illuminance * square radius

Lv = Ev * r²

= 3.5 * 2²

= 3.5 * 14

= 49 Candelabra