A particle moves in the xy plane with constant acceleration. At time zero, the particle is at x = 6 m, y = 8.5 m, and has velocity ~vo = (9 m/s) ˆı + (-2.5 m/s) ˆ. The acceleration is given by ~a = (4.5 m/s 2) ˆı + (3 m/s 2) ˆ. What is the x component of velocity after 3.5 s? Answer in units of m/s.

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2 April, 10:38

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Paityn Giles · Answer 1

24.75 m/s

Explanation:

Since it's only asking for the component we can use v_final=v_initial+at which then gives v_final=9+3.5*4.5=24.75 m/s