The cork from a champagne bottle slip through the hands of the waiter opening it, moving with an initial velocity v=11.8 m/s at an angle of 76.4 degrees above horizontal. A diner is sitting a horizontal distance d away when this happens. Assume the cork leaves the waiter's hands at the same vertical level as the diner and that the cork falls back to this vertical level when it reaches the diner Randomized variables v_o = 11.8 m/s theta = 76.4 degrees a) Calculate the time, t_d in seconds, for the cork to reach the diner b) Reacting quickly to avoid being struck, the diner moves 2.00m

Question

Maurice Benitez

Physics

17 February, 09:57

The cork from a champagne bottle slip through the hands of the waiter opening it, moving with an initial velocity v=11.8 m/s at an angle of 76.4 degrees above horizontal. A diner is sitting a horizontal distance d away when this happens. Assume the cork leaves the waiter's hands at the same vertical level as the diner and that the cork falls back to this vertical level when it reaches the diner Randomized variables v_o = 11.8 m/s theta = 76.4 degrees a) Calculate the time, t_d in seconds, for the cork to reach the diner b) Reacting quickly to avoid being struck, the diner moves 2.00m

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Anabel Calderon · Answer 1

The initial velocity of the cork is vo = 11.8 m/s

The angle is θ = 76.4 degrees

The time it takes for the cork to reach the diner is calculated using the formula:

t = 2 vo sin θ / g

t = 2 (11.8) sin 76.4 / 9.81

t = 2.34 s

It will take 2.34 seconds for the cork to reach the diner.