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10 July, 18:02

A stone is dropped from top of a tower of 50m high, simltaneously another stone is thrown upward with a speed of 20m/s find the time when them cross each other

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  1. 10 July, 18:30
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    At the time that I'll call ' Q ', the height of the stone that was

    dropped from the tower is

    H = 50 - (1/2 G Q²),

    and the height of the stone that was tossed straight up

    from the ground is

    H = 20Q - (1/2 G Q²).

    The stones meet when them's heights are equal,

    so that's the time when

    50 - (1/2 G Q²) = 20Q - (1/2 G Q²).

    This is looking like it's going to be easy.

    Add (1/2 G Q²) to each side.

    Then it says

    50 = 20Q

    Divide each side by 20: 2.5 = Q.

    And there we are. The stones pass each other

    2.5 seconds

    after they are simultaneously launched.
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