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3 July, 18:01

A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f (t) = 6.00t2-4.00t+3.00 is acting on the particle between t=0.00 seconds and t=5.00 seconds. find the speed v of the particle at t=5.00 seconds. express your answer in meters per second to three significant figures.

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  1. 3 July, 18:05
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    v = Integral (F/m) dtv=Integral (F/m) dt = â"50 (6t2â’4t+3) / 5dt=â"05 (6t2â’4t+3) / 5dt = 1/5â - (2t3â’2t2+3t) | (0,5) = 1/5â - (2t3â’2t2+3t) | (0,5) = 1/5â - (250â’50+15) = 1/5â - (250â’50+15) = 215/5=215/5 = 43m/s.
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