A 0.100-kilogram apple falls from a height of 1.50 meters to 1.00 meters. Ignoring frictional effects, what is the kinetic energy of the apple at this height?

Question

Adan

Physics

5 June, 07:15

A 0.100-kilogram apple falls from a height of 1.50 meters to 1.00 meters. Ignoring frictional effects, what is the kinetic energy of the apple at this height?

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Markus Hooper · Answer 1

Before the fall, at 1.50 m, all the energy is potential and none is kinetic.

As it's falling the apple has both kinetic and potential energies. The decrease in potential energy is equal to the increase in kinetic energy

KE = - ΔPE

= - mgΔh

= - (0.100 kg) (9.81 m/s²) (1.00 m - 1.50 m)

= 0.491 J