Ask Question
9 July, 18:58

A meteorite approaching a planet of mass M collides with an automatic space station orbiting the planet in a circular trajectory of radius R. The mass of the station is ten times as large as the mass of the meteorite. As a result of the collision, the meteorite sticks with the station which goes over to a new orbit with the minimum distance R/2 from the planet. Speed of the meteorite just before it collides with the space station is

+4
Answers (1)
  1. 9 July, 19:09
    0
    We are given with

    M = mass of planet

    R = radius of circular trajectory of the satellite

    ms = mass of the station

    mm = mass of the meteorite

    ms = 10 mm

    R/2 = new orbit distance

    The speed of the meteorite can be solved using the law of conservation of momentum

    ms vs + mm vm = (ms + mm) v

    Since the new orbit distance is half the original

    v = 2 vs

    Substitute and solve for vs
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A meteorite approaching a planet of mass M collides with an automatic space station orbiting the planet in a circular trajectory of radius ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers