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2 September, 17:39

A 256 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s. What is the length of the closed tube?

A. 1.35 m

B. 0.74 m

C. 0.34 m

D. 0.18 m

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Answers (1)
  1. 2 September, 18:07
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    Assuming our "closed tube" is closed at only one end, then

    v = fλ = f*4L/n

    where "n" is the harmonic number. So

    L = nv / 4f = n*346m/s / 4*256Hz = n*0.38 m

    Since the only option in your list that is an integer multiple of 0.38 m is 1.35 m

    I'd say that we're hearing the fourth harmonic.

    answer is

    A. 1.35 m
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