A platinum sphere with radius 1.65 cm is totally immersed in mercury. find the weight of the sphere, the buoyant force acting on the sphere, and the sphere/'s apparent weight. the densities of platinum and mercury are 2.14 * 104 kg/m3 and 1.36 * 104 kg/m3, respectively.

Question

Anabelle Bell

Physics

23 February, 12:06

A platinum sphere with radius 1.65 cm is totally immersed in mercury. find the weight of the sphere, the buoyant force acting on the sphere, and the sphere/'s apparent weight. the densities of platinum and mercury are 2.14 * 104 kg/m3 and 1.36 * 104 kg/m3, respectively.

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Ryan Chang · Answer 1

Gvn that, Radius r = 1.65cm then the Diameter d = 3.3 cm Volume V = 4/3pi * (D/3) ^3 = 4/3*3.14 * (3.3) ^3/8 = 4/3*3.14*35.937/8 = 4/3*3.14*4.492125 = 4/3*14.1052725 = 56.421.9/3 = 18.80703 dm^3 We know that gravity g=9.806m/s^2 p pt = 2.14 * 104 kg/m^3 = 21.4 p hg = 1.36 * 104 kg/m^3 = 13.6 Real Weight Wr = V*p pt*g = 18.80703*21.4*9.806 = 3946.625 N Buoyant force Fb = V*p hg*g = 18.80703*13.6*9.806 = 2508.136 N Apparent weight = Wr-Fb = 3946.625-2508.136 = 1438.489 N Therefore Apparent weight is 1438.489 N