Ask Question
4 March, 05:22

Initially sliding with a speed of 1.9 m/s, a 1.8 kg block collides with a spring and compresses it 0.35 m before coming to rest. what is the force constant of the spring?

+5
Answers (1)
  1. 4 March, 05:29
    0
    Let k = the force constant of the spring (N/m).

    The strain energy (SE) stored in the spring when it is compressed by a distance x=0.35 m is

    SE = (1/2) * k*x²

    = 0.5 * (k N/m) * (0.35 m) ²

    = 0.06125k J

    The KE (kinetic energy) of the sliding block is

    KE = (1/2) * mass*velocity²

    = 0.5 * (1.8 kg) * (1.9 m/s) ²

    = 3.249 J

    Assume that negligible energy is lost when KE is converted into SE.

    Therefore

    0.06125k = 3.249

    k = 53.04 N/m

    Answer: 53 N/m (nearest integer)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Initially sliding with a speed of 1.9 m/s, a 1.8 kg block collides with a spring and compresses it 0.35 m before coming to rest. what is ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers