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3 November, 19:04

An electrostatic paint sprayer has a potential of 25.0 kV that repels paint droplets onto a grounded object. What charge must a 0.63 mg drop of paint have to arrive at the object with a speed of 9 m/s? Give answer in terms of 10^-10 C.

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  1. 3 November, 19:15
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    10⁻⁶ C

    Explanation:

    Let the charge be Q

    Gain of energy in electric field

    = potential x charge

    = 25 x 10³ x Q

    Kinetic energy of droplet

    =.5 x. 63 x 10⁻³ x 9 x 9

    = 25.515 x 10⁻³ J

    So, equating the energy gained

    25 x 10³ x Q = 25.515 x 10⁻³

    Q = 10⁻⁶ C
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