A 76 kg pilot at an airshow performs a loop de loop with his plane. at the bottom of the 52-m radius loop, the plane is moving 48 m/s. determine the normal force acting upon the pilot.

Question

Giana Mclean

Physics

23 October, 14:52

A 76 kg pilot at an airshow performs a loop de loop with his plane. at the bottom of the 52-m radius loop, the plane is moving 48 m/s. determine the normal force acting upon the pilot.

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Answers (1)

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Lesly · Answer 1

The solution for this problem is:

At bottom, both centrifugal force and weight are performing in the same direction.

So we can say that, force would be computed by f = mg + mv^2 / r

= (76 x 9.81) + (76 x 48 x 48 / 52)

= 745.6 + 3367.4

Normal force = 4113 N is the answer