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8 August, 04:59

if a particle moving in straight line such that its position varies with time as x=5 (t-2) + 6 (t-2) ^2, then intial acceleration is

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  1. 8 August, 05:25
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    12

    Explanation:

    x = 5 (t - 2) + 6 (t - 2) ²

    x = 5t - 10 + 6 (t² - 4t + 4)

    x = 5t - 10 + 6t² - 24t + 24

    x = 6t² - 19t + 14

    Velocity is the derivative of position with respect to time:

    v = dx/dt

    v = 12t - 19

    Acceleration is the derivative of velocity with respect to time:

    a = dv/dt

    a = 12

    The particle's acceleration is constant at 12 (use appropriate units).
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