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25 October, 11:09

A 181-kg bookcase is at rest in the front office. A custodian pushes horizontally on the bookcase to try to move it. If it takes 584 N of force before the bookcase begins to move, find the coefficient of static friction between the bookcase and the floor.

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  1. 25 October, 11:26
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    The coefficient of static friction between the bookcase and the floor, μₓ = 0.3292

    Explanation:

    Given data,

    The mass of the bookcase, m = 181 kg

    The static frictional force of the bookcase, Fₓ = 584 N

    The gravitational normal force acting on the bookcase is, F = m g

    = 181 x 9.8

    = 1773.8 N

    The formula for static frictional force is

    Fₓ = μₓ F

    Where μₓ - the coefficient of the static friction

    μₓ = Fₓ / F

    = 584 N / 1773.8 N

    = 0.3292

    Hence, the coefficient of static friction between the bookcase and the floor, μₓ = 0.3292
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