A series RCL circuit includes a resistance of 280, an inductive reactance of 508, and a capacitive reactance of 315. The current in the circuit is 0.312 A. What is the voltage of the generator? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.

The voltage of the generator is 88.53volts

Explanation:

The voltage across the RLC AC circuit will be the voltage across the generator. It is expressed as

V = IZ and

Z² = R² + (Xl-Xc) ²

Z = √R² + (Xl-Xc) ² where;

Z is the impedance that oppose the flow of current in the resistor, capacitor and inductor in the circuit

I is the total current = 0.312A

R is the resistance in the circuit = 280ohms

Xl is the inductive reactance = 508ohms

Xc is the capacitive reactance = 315ohms

Substituting to this parameters to get the impedance Z we have;

Z = √280² + (508-315) ²

Z = √208² + (193) ²

Z = √80,513

Z = 283.75ohms

The voltage V of the generator = current * impedance

V = 0.312*283.75

V = 88.53Volts

The voltage if the generator is 88.53volts