A crate with a mass of m = 130 kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate and the deck is As-0.86. The coefficient of kinetic friction is μk-0.41. Randomized Variables m 130 kg μ,-0.86 Pk=0.41 25% Part (a) Write an expression for the minimum force, F, n, that must be applied to get the block moving from rest. Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining:5 (5% per attempt) detailed view 0 Submit Part (b) What is the magnitude of the force F, n in newtons? Part (c) Write an expression for the force F, that must be applied to keep the block moving at a constant velocity Part (d) what is the magnitude of the force F., in newtons?

Question

Lily Esparza

Physics

18 March, 08:15

A crate with a mass of m = 130 kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate and the deck is As-0.86. The coefficient of kinetic friction is μk-0.41. Randomized Variables m 130 kg μ,-0.86 Pk=0.41 25% Part (a) Write an expression for the minimum force, F, n, that must be applied to get the block moving from rest. Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining:5 (5% per attempt) detailed view 0 Submit Part (b) What is the magnitude of the force F, n in newtons? Part (c) Write an expression for the force F, that must be applied to keep the block moving at a constant velocity Part (d) what is the magnitude of the force F., in newtons?

+3

Answers (1)

Know the Answer?

Yesenia Love · Answer 1

a, b)

Minimum force required to move the crate

= maximum static friction

= μs x mg

= 0.86 x 130 x 9.8

= 1095.64 N

c, d) Force required to keep the crate in uniform motion or net force is zero.

F = maximum kinetic friction

= μk x mg

=.41 x 130 x 9.8

= 522.34 N