A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4m. determine the acceleration of the bike.

Given: Change of x is 35.4m, Velocity Final=7.10 m/s, Velocity Initial=0m/s

Find: Acceleration

Analysis:

Vf²=Vi²+2aΔx (Velocity final squared equals Velocity initial squared plus 2 times acceleration times change of x)

(7.10 m²/s) ² = (0 m/s) ²+2a (35.4 m)

50.41 m/s² = (70.8 m) a

a=0.712 m/s²