A superball of mass m is dropped vertically from a height, h. if the impact time with the floor is t, what is the average force on the ball

Force = mass * acceleration. Acceleration = deltaV/deltaT, where deltaV is change in velocity, and deltaT is change in time. Deltav = final Velocity because initial velocity is 0. (Final Velocity) ^2 = (initial velocity) ^2 + 2ad, where a is gravity acceleration of 9.8m/s^2, and d is the height. Final velocity = sqrt (2*9.8*h) = sqrt (19.6h). Therefore, Force = m*sqrt (19.6h) / deltaT.