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5 December, 13:04

What is the velocity of a beam of electrons that go undeflected when passing through crossed (perpendicular) electric and magnetic fields of magnitude 1.63*104V/m and 2.50*10-3T, respectively? me=9.11*10-31kg, e=1.60*10-19C.

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  1. 5 December, 13:11
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    Answer: V = 67808m/s

    Explanation:

    Parameter given

    E = 1.63*104V/m

    B = 2.50*10-3T

    V = E/B

    Velocity of the beam of electron = (Electric field/Magnetic field)

    V = (1.63*104V/m) : (2.5*10-3T)

    = 169.52 / 0.0025

    V = 67808m/s
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