Ask Question
24 November, 14:44

A screen is placed 50cm from a single slit illuminated with 690nm light. If the distance between the first and third dark fringes in the diffraction pattern is 3mm.

a) Find the width of the slit

used w = (2/lambdaL) / d to get 500 mm

b) Find the width of the central bright fringe using w = (2/lambdaL) / d.

+4
Answers (1)
  1. 24 November, 14:51
    0
    a) Distance of screen (D) = 50 X 10⁻²

    Wavelength of light λ = 690 x 10⁻⁹

    d = width of slit

    Distance between first and third dark fringe = 2 x fringe width

    = 2 x λD/d = 3 x 10⁻³

    d = 2 x 690 x 10⁻⁹ x 50 x 10⁻² / 3 x 10⁻³ = 0.23 mm

    b) Width of central bright fringe = 2 λD/d

    2 x 690 x 10⁻⁹ x 50 x 10⁻² / 23 x 10⁻⁵ m

    = 3 mm.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A screen is placed 50cm from a single slit illuminated with 690nm light. If the distance between the first and third dark fringes in the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers