A 49.5 gram super ball traveling at 25.5 m/s bounces off a brick wall and rebounds at 19.5 m/s. a high-speed camera records this event. if the ball is in contact with the wall for 4.25 ms, what is the magnitude of the average acceleration of the ball during this time interval

T = 4.25 ms = 4 x 10⁻³ s, the time for rebound

v₁ = 25.5 m/s, the impacting velocty

v₂ = - 19.5 m/s, the rebounding velocity (n the opposite directon)

The change in velocity is

v₂ - v₁ = - (25.5+19.5) = - 45 m/s

The acceleration is

a = (-45 m/s) / (4 s) = - 11.25 m/s²

The negative sign indicates that the final velocity is opposiye to the impact velocty.

Answer: The magnitude of the acceleration is 11.25 m/s²