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16 August, 09:30

A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass?

b.) What was the change in velocity of the object?

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  1. 16 August, 09:55
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    Impulse = change in momentum

    FΔt = Δp

    (53 N) (15 s) = Δp

    Δp = 795 kg m/s

    For constant mass:

    Δp = m Δv

    795 kg m/s = (12 kg) Δv

    Δv = 66.25 m/s

    Rounding to two significant figures, Δp = 800 kg m/s and Δv = 66 m/s.
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