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4 April, 05:23

What potential difference would an electron have to fall through to acquire a speed of 3.00*10^6 m/sec?

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  1. 4 April, 05:45
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    25.6 V

    Explanation:

    The kinetic energy of electron associated with its potential difference is given by eV which is equal to the 1/2 mv^2.

    m = 9.1 x 10^-31 kg, v = 3 x 10^6 m/s, e = 1.6 x 10^-19 C

    eV = 1/2 m v^2

    V = mv^2 / 2 e

    V = (9.1 x 10^-31) x (3 x 10^6) ^2 / (2 x 1.6 x 10^-19)

    V = 25.6 V
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